Fracisco s game involves 3 green 2 yellow 4 red and 3 black marbles.
Three marbles with 2 colors can be aranged.
This is the last question on my homework.
So let s say we have 4 slots here.
Any one of the three colors could be second.
Answer by edwin mccravy 18145 show source.
Since color are repeating so we use this formula 𝑛 𝑝1 𝑝2 𝑝3.
How many ways can i arrange 10 red marbles 5 white marbles and 6 blue marbles in a row.
Many of these arrangements are identical because same colored marbles are indistinguishable from one another.
Each of the 9 3 sets is equally likely to be drawn and 2 3 4 of them are successes so the probability of success is 2 3 4 9 3 24 84 2 7.
If he randomly draws three marbles from the bag without replacement what is the probability that he will draw yellow and then red and then black.
So each unlabelled order gives rise to 4 3 2 labelled orders.
Now with that out of the way let s think about how many different ways we can pick 4 colors.
So we raise three to the fourth power and subtract one to get eighty.
The same 4 colors we ve picked them in different orders.
Example 15 in how many ways can 4 red 3 yellow and 2 green discs be arranged in a row if the discs of the same colour are indistinguishable.
Enter your objects or the names of them one per line in the box below then click show me to see how many ways they.
They can be numbers letters people colors etc.
Here there are three choices for which purple marble goes with the two blue ones and three choices for which blue marble goes with the two purple ones.
And at first we care only about how many ways can we pick a color for that slot right there that first slot.
In order to arrive at only those permutations that are distinct division is requi.
A permutation of some number of objects means the collection of all possible arrangements of those objects.
1 slot 2 slot 3 slot and 4 slots.
Any one of the three colors could be first.
In how many different ways can these things be arranged in a row.
Any one of the three colors could be third and any one of the three colors could be fourth unless the first three marbles are red in which case the fourth marble must be one of the other two colors.
To build such a set you could pick either of the 2 red marbles any one of the 3 white marbles and any one of the 4 blue marbles so there are 2 3 4 such sets.