G 9 8 m s 2.
Time period of a satellite revolving earth is given as t height at which it orbits the earth.
Two medium earth orbits are notable.
If you know the satellite s speed and the radius at which it orbits you can figure out its period.
A satellite at this height takes 12 hours to complete an orbit.
From equation 3 the fundamental form of orbital velocity equation we get an equation of nearby orbit s orb.
This gives the height of a satellite above the earth s surface whose time period is same as that of earth s.
Radius of earth 6400 km.
A geostationary satellite is orbiting the earth at a height of 6r above its surface.
The time period of a satellite orbiting around the earth is given by.
From the following data calculate the period of revolution of the moon around the earth.
Where r is the radius of the earth.
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If time period of a satellite is 24 hrs.
Such a satellite appears to be stationary when observed from the earth s surface and is hence known as geostationary satellite.
Distance of moon from the earth 3 84 x 10 5 km.
The period of a satellite is the time it takes it to make one full orbit around an object.
Radius of earth r 6400 km 6 4 x 10 8 m radius of orbit of moon r 3 84 x 10 5.
Then r gm e t 2 4π 2 1 3 42400 km and h 36000 km.
In this case you add the distance from the center of the earth to the surface of the earth 6 38 10 6 meters to the satellite s height above the earth.
What is the time period of a satellite orbiting at a height of 2 5 r above the earth s surface.
Now if the height of the satellite h from the surface of the earth is negligible with respect to the radius of the earth then we can write r r h r as h is negligible.
T 5071 3600 1 408 h.
Neither the mass of the satellite nor the radius of it orbits.
The mean angular velocity of the earth around the sun is 1 per day.
The period of the earth as it travels around the sun is one year.
The speed of the satellite is 7 519 km s and the period of revolution of the satellite is 5930 s.
The semi synchronous orbit is a near circular orbit low eccentricity 26 560 kilometers from the center of the earth about 20 200 kilometers above the surface.
The speed of the satellite is 7 931 km s and the time of revolution of the satellite is 1 408 h.
T 2πr v c 2 x 3 142 x 6400 7 931 5071 s.
The time period of an earth stellite in circuarl orbit is independet fo.
The semi synchronous orbit and the molniya orbit.
The equation assumes that the satellite is high enough off the ground that it orbits out of the atmosphere.
